Wie zeigt man ein JavaScript datetime-Objekt im 12-Stunden-Format (AM/PM) an?
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Md. Juyel Rana
Punkte
537
antelove
Punkte
2552
function formatTime( d = new Date(), ampm = true )
{
var hour = d.getHours();
if ( ampm )
{
var a = ( hour >= 12 ) ? 'PM' : 'AM';
hour = hour % 12;
hour = hour ? hour : 12; // the hour '0' should be '12'
}
var hour = checkDigit(hour);
var minute = checkDigit(d.getMinutes());
var second = checkDigit(d.getSeconds());
// https://stackoverflow.com/questions/1408289/how-can-i-do-string-interpolation-in-javascript
return ( ampm ) ? `${hour}:${minute}:${second} ${a}` : `${hour}:${minute}:${second}`;
}
function checkDigit(t)
{
return ( t < 10 ) ? `0${t}` : t;
}
document.querySelector("#time1").innerHTML = formatTime();
document.querySelector("#time2").innerHTML = formatTime( new Date(), false );
<p>ampm true: <span id="time1"></span> (default)</p>
<p>ampm false: <span id="time2"></span></p>
Mitesh K
Punkte
624
const formatAMPM = (date) => {
try {
let time = date.split(" ");
let hours = time[4].split(":")[0];
let minutes = time[4].split(":")[1];
hours = hours || 12;
const ampm = hours >= 12 ? " PM" : " AM";
minutes = minutes < 10 ? `${minutes}` : minutes;
hours %= 12;
const strTime = `${hours}:${minutes} ${ampm}`;
return strTime;
} catch (e) {
return "";
}
};
const startTime = "2021-12-07T17:00:00.073Z"
formatAMPM(new Date(startTime).toUTCString())
sarkiroka
Punkte
1380
Vik2696
Punkte
337
function getDateTime() {
var now = new Date();
var year = now.getFullYear();
var month = now.getMonth() + 1;
var day = now.getDate();
if (month.toString().length == 1) {
month = '0' + month;
}
if (day.toString().length == 1) {
day = '0' + day;
}
var hours = now.getHours();
var minutes = now.getMinutes();
var ampm = hours >= 12 ? 'pm' : 'am';
hours = hours % 12;
hours = hours ? hours : 12;
minutes = minutes < 10 ? '0' + minutes : minutes;
var timewithampm = hours + ':' + minutes + ' ' + ampm;
var dateTime = monthNames[parseInt(month) - 1] + ' ' + day + ' ' + year + ' ' + timewithampm;
return dateTime;
}