Daten in Python-Array sortieren

Question

Wie sortiert man das unten stehende Array von Daten auf Python 2.4

 timestamps = ['2011-06-2', '2011-08-05', '2011-02-04', '2010-1-14', '2010-12-13', '2010-1-12', '2010-2-11', '2010-2-07', '2010-12-02', '2011-11-30', '2010-11-26', '2010-11-23', '2010-11-22', '2010-11-16']

Answer 1

>>> import datetime
>>> dates = [datetime.datetime.strptime(ts, "%Y-%m-%d") for ts in timestamps]
>>> dates.sort()
>>> sorteddates = [datetime.datetime.strftime(ts, "%Y-%m-%d") for ts in dates]
>>> sorteddates
['2010-01-12', '2010-01-14', '2010-02-07', '2010-02-11', '2010-11-16', '2010-11-
22', '2010-11-23', '2010-11-26', '2010-12-02', '2010-12-13', '2011-02-04', '2011
-06-02', '2011-08-05', '2011-11-30']

Answer 2

sorted(timestamps, key=lambda d: map(int, d.split('-')))

Answer 3

>>> import time
>>> timestamps = ['2011-06-2', '2011-08-05', '2011-02-04', '2010-1-14', '2010-12-13', '2010-1-12', '2010-2-11', '2010-2-07', '2010-12-02', '2011-11-30', '2010-11-26', '2010-11-23', '2010-11-22', '2010-11-16']
>>> timestamps.sort(key=lambda x: time.mktime(time.strptime(x,"%Y-%m-%d")))
>>> timestamps
['2010-1-12', '2010-1-14', '2010-2-07', '2010-2-11', '2010-11-16', '2010-11-22', '2010-11-23', '2010-11-26', '2010-12-02', '2010-12-13', '2011-02-04', '2011-06-2', '2011-08-05', '2011-11-30']

Answer 4

Wenn Sie sie in dasselbe Format sortieren, können Sie einfach die timestamps.sort()

Answer 5

map(lambda x:x[1], sorted(map(lambda a:[map(int,a.split('-')),a], timestamps)))

['2010-1-12',
 '2010-1-14',
 '2010-2-07',
 '2010-2-11',
 '2010-11-16',
 '2010-11-22',
 '2010-11-23',
 '2010-11-26',
 '2010-12-02',
 '2010-12-13',
 '2011-02-04',
 '2011-06-2',
 '2011-08-05',
 '2011-11-30']